Question

Need help. Have to finish this today!!!!

Answer 1

Explanation:

1)a ) Let the constant proportionality =k

Direct proportion.So, y = kx

Plugin y = 6 and x =2 and find k

6 = k*2

6/2 = k

k = 3

Constant proportionality = 3

b) y = 3x

When x = 7 ; y = 3*7 = 21

y = 21

c)When x = 9,

y = 3*9

y = 27

d) When y = 9,

9 = 3*x

9/3 = x

x = 3

e)when y = 30

30 = 3*x

30/3 =x

x = 10

3) y is inversely proportion to x³

`y =k(1)/(x^(3))\\\\3 =k *(1)/(2^(3))\\\\3=k*(1)/(8)\\\\3*8=k\\\\24 = k`

b) when x = 4

`y=24*(1)/(4*4*4)\\\\y=(3)/(8)`

c) When x = 6

`y = 24*(1)/(6*6*6)\\\\y=(1)/(9)`

d) When y = 24

`24= 24*(1)/(x^(3))\\\\x^(3)*24=24\\\\x^(3)=(24)/(24)\\\\x^(3)=1\\\\x = 1`