Question

The point stope form of the equation of the line that passes through (-4,-3) and (12, 1) is y-1 = (x-12). What is

the standard form of the equation for this line?

Answer 1

x-4y = 8

Explanation:

The standard form for the equation of a line is Ax+By=C where A is a positive integer and B and C are integers

First we need to find the slope

m = ( y2-y1)/(x2-x1)

m = (-3-1) / (-4-12)

=-4/-16

= 1/4

The point slope form is

y-1 = 1/4(x-12)

Multiply each side by 4

4(y-1 )= 4*1/4(x-12)

4(y-1) = x-12

4y -4 = x-12

Subtract 4y from each side

4y-4-4y = x-4y -12

-4 = x-4y -12

Add 12 to each side

-4+12 = x-4y -12+12

8 = x-4y

x-4y = 8

The standard form is x-4y = 8