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. A student adds 50 mL of Lead (II) Nitrate solution to 50 mL of potassium iodide. Each

solution is colorless, but when these two liquids are mixed, a yellow precipitate is
observed. What has most likely happened in the experiment?

User Tdh
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1 Answer

3 votes

Answer:

after the reaction between Lead (II) Nitrate solution and potassium iodide occur Lead(II) iodide was formed and it's yellow color.

Step-by-step explanation:

Pb(NO3)2 + KI = KNO3 + PbI2

User Indirect
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