Question

What is the value of k such that 5x-2y=9 and 6x+ky=4 are perpendicular?

Answer 1

15

5x-2y=9......(1)

6x+ky=4......(2)

slope of eqn i= -5/-2

=5/2

slope of eqn ii = -6/k

since the line are perpendicular

5/2 * -6/k = -1

-30= -2k

k=15