Question

What is the average Mw for a fatty acid mixture whose fats (1 gram) required 0.0034 equivalents of NaOH to titrate. Remember: 1 Fatty acid has 1 equivalent.

1. Ew = Mw (#H+)
2. Ew = mass/eq
a.) 294.12 g/mol
b.) 145.04 g/mol
c.) 345.56 g/mol
d.) 132.04 g/mol

Answer 1

a.) 294.12 g/mol

Step-by-step explanation:

1 equivalent of fatty acid reacts with 1 equivalent of NaOH.

As in the titration are required 0.0034 equivalents of NaOH, the equivalents of fatty acids = moles of fatty acids are:

0.0034 moles of fatty acids

Molar mass is defined as the ratio between mass of substance in a determined amount of moles. The mass of the fats was 1 gram, that means the molar mass is:

1g / 0.0034moles =

294.12g/mol

Right option is:

a.) 294.12 g/mol