Question

harold threw a baseball 3 meters harold is 2 meters tall. how fast did he throw the ball and how long was it in the air

Answer 1

u = 7.74 m/s and t = 1.82 s

Step-by-step explanation:

Given that,

Harold threw a baseball 3 meters.

Harold is 2 meters tall.

The vertical distance = 3m

The final velocity at the maximum height is 0.

Let u is the initial velocity of the baseball. Using the first equation of motion to find it as follows :

`v^2-u^2=2as`

Here, a = -g

`v^2-u^2=-2gs\\\\u=√(2gs) \\\\=√(2* 10* 3) \\\\=7.74\ m/s`

He has thrown it with the speed of 7.74 m/s

Let t is the time taken by the ball to fall on the ground.

Harold is 2 meters tall. Using second equation of motion to find it.

u = -7.74 (as downward direction is taken as positive)

`s=ut+(1)/(2)at^2\\\\2=-7.74t+5t^2\\\\t=1.82\ s`

Hence, this is the required solution.