Question

write the equation of the line, in standard form, that is perpendicular to y=3x-2 and passes through (-7,2)

Answer 1

x+3y=-1

Explanation:

y=3x-2 so m=3 old slope

the new slope must be -1/3 (opposite reciprocal of the old slope).

y-y0=m*(x-x0)

y-2=-1/3*(x-(-7))

y-2=-1/3x-1/3*7

y-2=-1/3x-7/3

3y-6=-x-7

The standard form for linear equations in two variables is Ax+By=C.

x+3y=6-7

x+3y=-1