Answer:
(2x^2 + x-7)/3x+ 3
Explanation:
Here, we want to write the following as a single fraction;
2x-1/3 - 2/x + 1
That will be;
(2x-1)(x + 1) -2(3)/3(x+ 1)
= 2x^2+ 2x-x-1-6/3(x + 1)
= (2x^2+x-7)/3(x+1)
= (2x^2 + x-7)/3x+ 3
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