Question

Another day, another math problem 3

Answer 1

`2√(x+1)-3\\domain:[-1, \infty)`

Explanation:

`g(h(x)) = 2(√(x+1))-3\\g(h(x)) = 2√(x+1) - 3\\`

the function is only defined when (x+1) >= 0 (since square root) so the domain is when x >= -1