Answer:
The solution is:
![6x-12-x\le \:3\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:3\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:3]\end{bmatrix}](https://img.qammunity.org/2021/formulas/mathematics/college/80gvt7g3d4s6jov63waqc9e5p3l5gpxi26.png)
The graph of the solution is attached below.
Both the number line and graph is attached below.
Explanation:
Note: you missed to add the graph options. Therefore, I am solving the inequality and adding the corresponding graph which would anyways clear your concept.
Given the inequality expression

Group like terms

Add similar elements: 6x-x=5x

Add 12 to both sides

simplify

Divide both sides by 5

simplify

Therefore, the solution is:
![6x-12-x\le \:3\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:3\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:3]\end{bmatrix}](https://img.qammunity.org/2021/formulas/mathematics/college/80gvt7g3d4s6jov63waqc9e5p3l5gpxi26.png)
- The graph of the solution is attached below.
Both the number line and graph is attached below.