Answer:
B
Explanation:
Here, we want to find the point-slope equation of the line
We start by getting the y-intercept of the line which is y = 3
The general equation of a straight line is;
y = mx + b
where b is the y-intercept
So, we have;
y = mx + 3
Now, to get m , we insert the point given on the like which is (2,-5)
x = 2 and y = -5
-5 = 2m + 3
-8 = 2m
m = -8/2
m = -4
So the equation of the line is;
y = -4x + 3
This is same as option B