Question

A ball is thrown straight upward with a velocity of 14 m/s. What is the maximum height

reached by the ball?
(1 Point)
10 m
20 m
14 m
32 m

Answer 1

Hello!

`\large\boxed{d = 10 m}`

When the ball reaches its maximum height, the velocity equals 0. We can use the kinematic equation:

vf = vi + at, where:

vf = final velocity (0)

vi = initial velocity (14 m/s)

a = acceleration due to gravity, or 9.8 m/s (downwards)

t = time, which will be solved for.

Plug in the given values:

0 = 14 - 9.8(t)

-14 = -9.8(t)

t ≈ 1.429 sec

Solve for the distance traveled using the kinematic equation:

d = 1/2(vf + vi)t

Plug in the values:

d = 1/2(14 + 0)(1.429)

d = 1/2(14 · 1.429)

d ≈ 10 m