Question

An ideal step-down transformer is needed to reduce a primary voltage of 120 V to 6.0 V. What must be the ratio of the number of turns in the secondary to the number of turns in the primary

Answer 1

`N_s : N_p = 20 : 1`

Step-by-step explanation:

From the question we are told that

The primary voltage is
`V_p = 120 \ V`

The secondary voltage is
`V_s = 6 \ V`

Generally from the transformer equation we have that

`(V_p)/(V_s) = (N_p)/(N_s)`

So

`(120)/(6) = (N_p)/(N_s)`

=>
`(N_p)/(N_s) = 20`

Therefore the ratio of the number of turns in the secondary to the number of turns in the primary is

`N_s : N_p = 20 : 1`