Answer:
x = 0.05
x = 1.57
Explanation:
The given equation is:
![e^x-\ln 2x = 3.7](https://img.qammunity.org/2021/formulas/mathematics/high-school/puzi851f9mgdsdiy2ebv3l49t9r6ory1b5.png)
Moving all terms to the left side:
![e^x-\ln 2x - 3.7=0](https://img.qammunity.org/2021/formulas/mathematics/high-school/r01w71acg01j5ysmptnwlz0wluzz8bz55s.png)
Now we define a function:
![y=f(x)=e^x-\ln 2x - 3.7](https://img.qammunity.org/2021/formulas/mathematics/high-school/mjqdauuz2npy5ime20t4elgmakmsombex2.png)
The solutions of the equation are the values of x such that y=0.
Since the function cannot be solved by algebraic methods, we use a graphing tool.
Those points where the graph crosses the x-axis are solutions of the equation.
Please refer to the graph in the figure below.
We can clearly identify there are two solutions at
x = 0.05
x = 1.57