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1 vote
What is (-2xy^3z^-2)^3(2x^2y^4z)^-2 simplified?

User Librik
by
4.3k points

2 Answers

4 votes
This seems like a joke but whatever

=
-2y/xz^8

I would show the steps but it’s a lot lol
User Abe
by
4.8k points
4 votes

Answer: 3 23 divided by 22 = 2(3 - 2) = 21 = 2 think it’s 2

Step-by-step explanation: Changes made to your input should not affect the solution:

(1): "^-2" was replaced by "^(-2)".

(2): "y4" was replaced by "y^4".

STEP

1

:

Equation at the end of step 1

(((0-((2x•(y3))•z))-2)3)•(((2x2•y4)•z)-2)

STEP

2

:

Equation at the end of step

2

:

(((0 - (2xy3 • z)) - 2)3) • (2)(-2)x(-4)y(-8)z(-2)

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Simplify ( -2xy3z-2 )3

Put the exponent aside and simplfy the base by pulling out like factors :

-2xy3z-2 = -2 • (xy3z+1)

Remember the 4th law of exponents : (a • b)m= am• bm

Retract the exponent and apply the 4th law to the simplified base: ( -2 • (xy3z+1) )3 = (-2)3 • (xy3z+1)3

Trying to factor as a Sum of Cubes:

4.2 Factoring: xy3z+1

Put the exponent aside, try to factor xy3z+1

Theory : A sum of two perfect cubes, a3 + b3 can be factored into :

(a+b) • (a2-ab+b2)

Proof : (a+b) • (a2-ab+b2) =

a3-a2b+ab2+ba2-b2a+b3 =

a3+(a2b-ba2)+(ab2-b2a)+b3=

a3+0+0+b3=

a3+b3

Check : 1 is the cube of 1

Check : x 1 is not a cube !!

Ruling : Binomial can not be factored as the difference of two perfect cubes

Dividing exponents:

4.3 23 divided by 22 = 2(3 - 2) = 21 = 2

Final result :

-2 • (xy3z + 1)3

————————————————

x12y24z6

User Bbtrb
by
4.3k points