Question

Help needed! Thank you!

Answer 1

Part 1

`(f\circ g)(x)=f(g(x))=((1)/(x))/((1)/(x)-3)`

Multiplying the numerator and denominator by x,

`(f\circ g)(x)=\boxed{(1)/(1-3x)}`

Part 2

The domain for this function is all values of x except for when the denominator equals 0 (because then, it would be undefined).

The denominator is equal to 0 when x=1/3, so the domain is
`\boxed{x \\eq (1)/(3)}`