Question

What is an equation of the line that passes through the point (-2,-3)(−2,−3) and is parallel to the line 5x+2y=14

Answer 1

y=5/2x+2

Explanation:

rearrage equation: y=5/2x-7

new slope is same: y=5/2x+b

substitue point (-2,-3):

-3=5/2(-2)+b

-3=-5+b

-3+5=b

2=b