Question

Anyone able to help with this one? The volume of a gas sample is 550 mL and the pressure is 1.8 atm. What will the new volume of the gas be if the pressure increases to 2.2 atm? Round your answer to the correct number of significant figures.

Answer 1

V₂ = 450 mL

Step-by-step explanation:

Because you are dealing solely with pressure and volume, you can use Boyle's Law to find the missing value. The equation looks like this:

P₁V₁ = P₂V₂

In this formula, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You have been given values for all of the variables except for "V₂". Thus, you can substitute the given values into the equation and simplify to find the answer. The final answer should have 2 sig figs to match the given values.

P₁ = 1.8 atm V₁ = 550 mL

P₂ = 2.2 atm V₂ = ?

P₁V₁ = P₂V₂ <----- Boyle's Law equation

(1.8 atm)(550 mL) = (2.2 atm)V₂ <----- Plug given values in

990 = (2.2 atm)V₂ <----- Multiply 1.8 and 550

450 = V₂ <----- Divide both sides by 2.2

Answer 2

450 ML

Step-by-step explanation:

Given:

Volume of gas sample: 550 mL Pressure: 1.8 atm plus 2.2 atm

To find:

The new volume of the gas after the pressure increases to 2.2 atm.

___

steps

⇒
`V_1P_1=V_2P_2`

⇒
`(550\text{ml})(1.8\text{atm})`

⇒
`=(x)(2.2\text{atm})`

⇒
`x=((550)(1.8))/(2.2)`

⇒
`x=450\text{ml}`