Question

A 30 kg table is pushed forward with a force of 12 N. Friction pushes back with a

force of 5 N. What is the net force?!!

Answer 1

a = 0.23 [m/s²]

Step-by-step explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces applied [N]

m = mass = 30 [kg]

a = acceleration [m/s²]

Now we can use Newton's second law, with forces pointing to the right as positives and negative forces pointing towards the left.

`12 - 5 = 30*a\\7 = 30*a\\a = 0.23 [m/s^(2) ]`