Question

The velocity of a 48.0 g shell leaving a 2.95 kg rifle is 391. m/s. What is the recoil velocity of the rifle?

Answer 1

Hi there!

`\large\boxed{ -6.36m/s}`

Use the equation:

`v_(2) = -(m_(1))/(m_(2)) v_(1)`

Where m2 and v2 deal with the larger object, and m1 and v1 with the smaller object. Plug in the given values:

v2 = ?

m1 = 0.048 kg (converted)

m2 = 2.95

v1 = 391

`v_(2) = -(0.048)/(2.95) *391`

`v_(2) = -6.36m/s`