Question

How many grams of molybdenum(Mo) are in 2.68E24 atoms of Mo?

Answer 1

427 g Mo

General Formulas and Concepts:

Chemistry

Atomic Structure

• Reading a Periodic Table
• Using Dimensional Analysis
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Step-by-step explanation:

Step 1: Define

2.68E24 atoms Mo or 2.68 × 10²⁴ atoms Mo

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Mo - 95.94 g/mol

Step 3: Convert

`2.68 \cdot 10^(24) \ atoms \ Mo((1 \ mol \ Mo)/(6.022 \cdot 10^(23) \ atoms \ Mo) )((95.94 \ g \ Mo)/(1 \ mol \ Mo) )` = 426.966 g Mo

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

426.966 g Mo ≈ 427 g Mo