Question

A carton has a length of fraction 2 and 2 over 3 feet, width of fraction 1 and 1 over 8 feet, and height of fraction 1 and 1 over 5 feet. What is the volume of the carton?

fraction 3 and 3 over 5 cubic feet
fraction 4 and 1 over 5 cubic feet
fraction 5 and 2 over 5 cubic feet
fraction 7 and 1 over 5 cubic feet

Answer 1

Given:

Length of a carton =
`2(2)/(3)` feet

Width of a carton =
`1(1)/(8)` feet

Height of a carton =
`1(1)/(5)` feet

To find:

The volume of the carton.

Solution:

We know that, volume of the carton is

`V=length* width * height`

Putting the values, we get

`V=2(2)/(3)* 1(1)/(8) * 1(1)/(5)`

`V=((2* 3)+2)/(3)* ((1* 8)+1)/(8) * ((1* 5)+1)/(5)`

`V=(8)/(3)* (9)/(8) * (6)/(5)`

Taking LCM, we get

`V=(18)/(5)`

`V=3(3)/(5)`

So, the volume is
`3(3)/(5)` cubic feet.

Therefore, the correct option is A.