Question

Find the equation of the line that passes through the given points. Write the equation in slope-intercept form.

(-2.7) and (-1,5)

Answer 1

The equation in the slope-intercept form will be:

• y = -2x + 3

Explanation:

Given the points

• (-2, 7)

• (-1, 5)

Finding the slope between the points

`\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)`

`\left(x_1,\:y_1\right)=\left(-2,\:7\right),\:\left(x_2,\:y_2\right)=\left(-1,\:5\right)`

`m=(5-7)/(-1-\left(-2\right))`

`m=-2`

We know that the slope-intercept of line equation is

`y=mx+b`

where m is the slope and b is the y-intercept

substituting m = -2 and the point (-2, 7) to find the y-intercept 'b'

y = mx+b

7 = -2(-2) + b

7 = 4 + b

b = 7-4

b = 3

so the y-intercept = b = 3

substituting m = -2 and b = 3 in the slope-intercept form of line equation

y = mx+b

y = -2x + 3

Thus, the the equation in the slope-intercept form will be:

• y = -2x + 3