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Dejah is proving that perpendicular lines have slopes that are opposite reciprocals. She draws line s and labels two points on the line as (−a, 0) and (0, b).

Enter the answers, in simplest form, in the boxes to complete the proof.

Dejah is proving that perpendicular lines have slopes that are opposite reciprocals-example-1
User Nelluk
by
5.1k points

2 Answers

5 votes

Answer:

  • b/a; (b, 0); -a/b; -1

Explanation:

Given:

Slope of Line S - (b - 0)/(0 - (-a)) = b/a

Remember the clockwise rule:

(-a, 0) → (0, a)

(0, b) → (b, 0)

Slope of line T - (0- a)/(b - 0) = -a/b = -a/b

The product of slopes: b/a × (-a/b) = -1

So, finally, our answer is:

  • b/a; (b, 0); -a/b; -1

Carry On Learning!

User Adam Parkin
by
5.3k points
4 votes

Answer:

  • b/a; (b, 0); -a/b; -1

Explanation:

Slope of line s:

  • (b - 0)/(0 - (-a)) = b/a

Rotation 90 clockwise rule:

  • (-a, 0) → (0, a)
  • (0, b) → (b, 0)

The slope of line t:

  • (0- a)/(b - 0) = -a/b = -a/b

The product of slopes:

  • b/a*(-a/b) = -1
User Dean Xu
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4.9k points