23.3k views
4 votes
SOMEONE HELP ASAP!!!!!​

SOMEONE HELP ASAP!!!!!​-example-1
User Coelacanth
by
6.3k points

1 Answer

1 vote

Answer:

A. y=
(3)/(2)x-3

B.y=
(-3)/(4)x-3

Explanation:

Okay so essentially, the first thing you need to do is find the slope and y intercept for each equation. To find the slope, I like to look at the two points and divide the rise (How much it goes up or down) by the run (How much it moves left or right). For A the rise is 6 and the run is 4, so the slope is 6/4 or 3/2. To find the equation for A, you also need the y-intercept which is just the y value (how high up or down) it is when it crosses the y axis. In graph a, this is at -3. Because the equation of a line is y=mx+b (m being slope and b being y intercept), we know the equation for a is y=
(3)/(2)x-3. We can do the same thing for B. The rise is -3 and the run is 4, so the slope is -3/4. The y value when x is equal to zero is 2, so that is the y intercept. The equation is y=
(-3)/(4)x-3

User John Trammell
by
7.6k points