Question

Im not sure what to do

Answer 1

`h(-1)=(-2)/(3)`

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Function Notation

Explanation:

Step 1: Define

`h(x)=(2x-6)/(4x^2+8)`

h(-1) is x = -1

Step 2: Evaluate

1. Substitute:
   `h(-1)=(2(-1)-6)/(4(-1)^2+8)`
2. Exponents:
   `h(-1)=(2(-1)-6)/(4(1)+8)`
3. Multiply:
   `h(-1)=(-2-6)/(4+8)`
4. Subtract:
   `h(-1)=(-8)/(4+8)`
5. Add:
   `h(-1)=(-8)/(12)`
6. Simplify:
   `h(-1)=(-2)/(3)`