Question

I NEED HELP ASAP!!

The Johnson party had a good hunt. They bagged a total of 26 deer which included some
big bucks, little bucks and some does. The number of does is 5 more than twice the amount of
little bucks. The number of big bucks was half as many as little bucks. How many big bucks,
little bucks and does did the party get?

Answer 1

9514 1404 393

Answer:

• 3 big bucks
• 6 little bucks
• 17 does

Explanation:

Let B, L, D represent the numbers of big bucks, little bucks, and does, respectively.

B + L + D = 26 . . . . . . total bagged

D = 5 + 2L . . . . . . . . . 5 more does than twice the number of little bucks

B = L/2 . . . . . . . . . . . . half as many big bucks as little bucks

__

We can substitute for B and D in the first equation:

L/2 + L + (5 +2L) = 26

7/2L = 21 . . . . . . . . . . . . . subtract 5, collect terms

L = 6 . . . . . . . . . . . . . . . . . multiply by 2/7

D = 5 + 2·6 = 17

B = 6/2 = 3

The party bagged 3 big bucks, 6 little bucks and 17 does.