Answer:
![\bold{(1)/(4)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/fa4y3pjq2c5wqakobc4qkgvk2a7quauj88.png)
Explanation:
Number of red tiles = 1
Number of yellow tiles = 1
Number of blue tiles = 1
Number of green tiles = 1
Total number of tiles = 4
Also, given that there is a standard dice with faces numbered from 1 to 6.
Formula for probability of an event E can be observed as:
![P(E) = \frac{\text{Number of favorable cases}}{\text {Total number of cases}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/aeg3h4h3bbx73banosb6zhsdb88ck3qbng.png)
First of all, let the event
be event that a red or yellow tile is chosen.
Number of favorable cases = 2
Total number of cases = 4
![P(A) = (2)/(4) = (1)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/95cmlhzz8bstt67kt338ohefcqrwtvxkld.png)
Let the event
be event that a number between 1 and 3.
Number of favorable cases = 3
Total number of cases = 6
![P(B) = (3)/(6) = (1)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qftv46qsiy22fb782ezknjd55y6uqy1p5q.png)
![P(A\ and\ B) = P(A).P(B)](https://img.qammunity.org/2021/formulas/mathematics/high-school/7uxy1xyeqgjk6hwsi94kzlq2078imkoy97.png)
![P(A\ and\ B) = (1)/(2).(1)/(2) = \bold{(1)/(4)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/nfqr1h8tatnx6ph79dct4uk7zf8v62u9up.png)