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A sample of oxygen has a volume of 25.00 mL with a pressure of 2.0 atm. What pressure (in atm) will the sample of O2 gas occupy at 100.0 mL?

1 Answer

4 votes

Answer:

0.5 atm

Step-by-step explanation:

The final pressure can be found by using the formula for Boyle's law which is


P_1V_1 = P_2V_2

Since we are finding the new pressure


P_2 = (P_1V_1)/(V_2) \\

From the question we have


P_2 = (25 * 2)/(100) = (50)/(100) = (1)/(2) \\

We have the final answer as

0.5 atm

Hope this helps you

User Pugmarx
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