Question

How to write y-2=-1/3 (x+6) in standard form and why PLZ HELP

Answer 1

x + 3y = 0

Explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y - 2 = -
`(1)/(3)` (x + 6) ← distribute

y - 2 = -
`(1)/(3)` x - 2 ( add 2 to both sides )

y = -
`(1)/(3)` x ( multiply through by 3 to clear the fraction )

3y = - x ( add x to both sides )

x + 3y = 0 ← in standard form

Answer 2

`y-2=-(1)/(3)(x+6)\\y=-(1)/(3)(x+6)+2`

Simply move -2 to another side.

`y=-(x)/(3)-2+2`

Distribute -1/3 in (x+6)

`y=-(x)/(3)` ---> Answer