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The weight of one ticket is approximately 1.67 × 10-4 g. Write the numerical value without scientific notation.

User Lyxera
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1 Answer

4 votes

Answer:

0.000167 g

Explanation:


1.67 * {10}^( - 4) \: g\\ \\ = 0.000167 \: g

User SuperDougDougy
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