Question

an athlete whirls an 8.71 kg hammer tied to the end of a 1.5 m chain in a simple horizontal circle where you should ignore any vertical deviations the hammer moves at the rate of 1.16 rev/s what is the tension in the chain

Answer 1

T = 692.42 N

Step-by-step explanation:

Given that,

Mass of hammer, m = 8.71 kg

Length of the chain to which an athlete whirls the hammer, r = 1.5 m

The angular sped of the hammer,
`\omega=1.16\ rev/s=7.28\ rad/s`

We need to find the tension in the chain. The tension acting in the chain is balanced by the required centripetal force. It is given by the formula as follows :

`F=m\omega^2r\\\\=8.71* (7.28)^2* 1.5\\\\=692.42\ N`

So, the tension in the chain is 692.42 N.