Question

How many grams of aluminum

chloride, AlCl3, form when 0.25 mol
Al react?

2AI+ 3Cl₂ → 2AICI 3

[?] g AICI 3

Answer 1

From the equation, we know that for every 2 moles of aluminum consumed, 2 moles of aluminum chloride are produced.

This means that if 0.25 moles of Al react, then 0.25 moles of aluminum chloride are produced.

• The atomic mass of Al is 26.9815385 g/mol.
• The atomic mass of Cl is 35.45 g/mol.

So, the formula mass of aluminum chloride is:

• 26.9815385+3(35.45)=133.3315385 g/mol.

Thus, 0.25 moles have a mass of:

• (133.3315385)(0.25), which is about 33 g (to 2 sf)