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How many times does the quadratic function below intersect the x-axis?
y=x^2+10x+25​

How many times does the quadratic function below intersect the x-axis? y=x^2+10x+25​-example-1
User James Broad
by
2.8k points

2 Answers

24 votes
24 votes

Answer:

A. 1

Explanation:

To find the x-intercept, substitute 0 for y and solve for x.

x-intercept(s): (-5,0)

Considering (-5,0) is the only intersection on the x-axis, 1 is your answer.

If you want a visual of this, I recommend you use the Desmos graphing calculator to input your equation. It will show you what the curved line looks like.

User Vojtech Trefny
by
2.4k points
22 votes
22 votes
To find how many times the quadratic function intersects the x-axis, set y = 0

y = x^2+10x+25
0 = x^2+10x+25
Factor the right hand side
0 = (x+5)(x+5)
x + 5 = 0
x = - 5

Therefore, the quadratic equation intersects the x-axis at one point (x = -5)
User Mike Lane
by
3.1k points
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