Question

What are the solutions to the quadratic equation below in factored form?

(10x + 5)(11x - 44) = 0
= ½, x = 4
0x=
0 x = 2, x = -4
0x = 2, x = 4
○ x = − ½, x = 4

Answer 1

• (10x+5)(11x-44)=0
• 10x(11x-44)+5(11x-44)=0
• 110x²-440x+55x-220=0
• 110x²-385x-220=0

On solving

• x=-1/2 or x=4

Answer 2

D.) x = − ½, x = 4

Step-by-step explanation:

`\rightarrow \sf (10x + 5)(11x - 44) = 0`

set the factors to zero

`\rightarrow \sf 10x + 5 = 0, \ 11x - 44 = 0`

exchange the sides

`\rightarrow \sf 10x = -5, \ 11x = 44`

exchange the sides

`\rightarrow \sf x = -(5)/(10) , \ x = (44)/(11)`

simplify the following

`\rightarrow \sf x = -(1)/(2) , \ x =4`