191k views
2 votes
A right triangle of hypotenuse 13 cm and

one of its sides 12 cm is made to revolve
taking side 12 cm as its axis. Find the
volume and curved surface area of the solid
so formed.

User Ubernator
by
5.8k points

1 Answer

0 votes

9514 1404 393

Answer:

  • volume: 100π cm³ ≈ 314.2 cm³
  • area: 65π cm² ≈ 204.2 cm²

Explanation:

The other leg of the right triangle is found from the Pythagorean theorem:

r² + 12² = 13²

r = √(169 -144) = √25 = 5

The solid of revolution is a cone with a radius of 5, a height of 12, and a slant height of 13.

The volume is given by ...

V = (1/3)πr²h

V = (1/3)π(5 cm)²(12 cm) = 100π cm³ . . . volume

__

The lateral surface area is given by ...

LA = πrh . . . where h is the slant height

LA = π(5 cm)(13 cm) = 65π cm² . . . curved surface area

User Ravenspoint
by
5.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.