Question

A 2000 kg test car travels around a circular track with a radius of 100 m. If the

magnitude of the centripetal acceleration is 3 m/s2, what is the car's speed?

Answer 1

V=0.38 m/s

Step-by-step explanation:

ac=3 m/s^2

m=2000kg

r=100m

ac=mv^2/r

Solve for v^2

3=2000(v^2)/100

3=20v^2

3/20=.15

sqrt of .15= 0.38 m/s

V=0.38 m/s