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What is the equation of a line perpendicular to y-2=-2/3(x+1) and passing through the point (4,1) PLS HELP
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What is the equation of a line perpendicular to y-2=-2/3(x+1) and passing through the point (4,1)

PLS HELP

User Jan Tajovsky
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1 Answer

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Answer: y = (1/3)*x - 5

Step-by-step explanation: Hope this helps!

User AndrewJM
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