Question

Point
`P^1` is the image of P(6,0) under the translations (x, y) → (x - 6, y - 1) What are the coordinates of
`P^1`?

Answer 1

thanks for the points doe

Explanation:

Answer 2

(0, -1)

Explanation:

(x, y) → (x - 6, y - 1)

Apply the rule to point 'P'.

`(6,0)\rightarrow(6-6,0-1)\rightarrow\boxed{(0,-1)}`

Hope this helps.