Question

Write the vertex form of y=4x^2+16x-48

Answer 1

the vertex form :

4(x − (-2))² - 64

Explanation:

4x²+16x-48

= 4(x² + 4x) - 48

= 4(x² + 4x + 4 - 4) - 48

= 4(x² + 4x + 4) - 4×4 - 48

= 4(x + 2)² - 16 - 48

= 4(x + 2)² - (16 + 48)

= 4(x + 2)² - 64

= 4(x − (-2))² - 64