Question

1 of 5

Find the first three terms of the sequence below.
2.
Tn = n' + 3n + 4
Ti =
T2 =
T3 =​

Answer 1

`T_1 = 8`

`T_2 = 14`

`T_3 = 22`

Explanation:

Given

`T_n = n^2 + 3n + 4`

Required:

Find the first 3 terms

To do this, we take the values of n to be 1,2 and 3.

For the first term; n = 1

`T_n = n^2 + 3n + 4`

`T_1 = 1^2 + 3*1 + 4`

`T_1 = 1+ 3+ 4`

`T_1 = 8`

For the second term; n = 2

`T_n = n^2 + 3n + 4`

`T_2 = 2^2 + 3 * 2 + 4`

`T_2 = 4 + 6+ 4`

`T_2 = 14`

For the third term; n = 3

`T_n = n^2 + 3n + 4`

`T_3 = 3^2 + 3 * 3 + 4`

`T_3 = 9 + 9 + 4`

`T_3 = 22`