Question

There are 5 white balls. 8 red balls, 7 yellow balls, and 4 green balls in a container. A ball is chosen randomly. Find the probability of the following events.

1.What is the probability of choosing

green?
Answers:________ work space:______

2. What is the probability of choosing

red?
Answers:________ work space:______

3. What is the probability of choosing

neither white nor green?
Answers:________ work space:_______

4. . What is the probability of choosing

other than yellow?
Answers:________ work space:_______

5. What is the probability of choosing

purple?
Answer:_________ work space:_______​

Answer 1

Given :

• White balls = 5
• Red balls = 8
• Yellow balls = 7
• Green balls = 4

Answer 1 :-

We know that,

• P (E) = No. of favourable outcomes / Total number of outcomes.

>> Total no. of outcomes = 5 + 8 + 7 + 4

>> Total no. of outcomes = 24

As there are 4 green balls. Therefore,

• P (E) = 4 / 24
• P (E) = 2 / 12
• P (E) = 1 / 6

Answer 2 :-

We know that,

• P (E) = No. of favourable outcomes / Total number of outcomes.

>> Total no. of outcomes = 5 + 8 + 7 + 4

>> Total no. of outcomes = 24

As there are 8 red balls. Therefore,

• P (E) = 8 / 24
• P (E) = 4 / 12
• P (E) = 2 / 6
• P (E) = 1 / 3

Answer 3 :-

We know that,

• P (E) = No. of favourable outcomes / Total number of outcomes.

>> Total no. of outcomes = 5 + 8 + 7 + 4

>> Total no. of outcomes = 24

As there are 15 balls that are neither green nor white. (Red balls+ yellow balls)

• P (E) = 15 / 24
• P (E) = 5 / 8