Answer:
Explanation:
The problem title suggests you might solve this problem by completing the table for 9 tickets. To answer the questions, you would compare your table entries, and subtract one from the other to find the difference in cost.
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table
The left column is the number of tickets. We want to find the costs for 9 tickets, so 9 goes in that column.
The center column is the cost of 9 tickets for Aquarium. Each ticket costs $14.50, so the cost for 9 tickets is ...
9×$14.50 = $130.50
The right column is the cost of 9 tickets for Wave Pool. Since 9 is more than 4, the cost per ticket is $12.25, and the total cost for 9 tickets is ...
9×$12.25 = $110.25
Then the bottom row of the table is ...
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least cost
Clearly, the $110.25 cost at Wave Pool is less than the $130.50 cost at Aquarium. Wave Pool will cost the least for 9 tickets.
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difference
The difference in cost is ...
$130.50 -110.25 = $20.25
Wave Pool will cost $20.25 less.
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Alternate solution
You recognize that for a group of 9, the Wave Pool tickets are $12.25 each, which is less than the $14.50 per-ticket cost at Aquarium. Making this comparison, you know the least-cost event is Wave Pool.
The difference in cost is the product of the difference in ticket price and the number of tickets:
9×($14.50 -12.25) = 9×$2.25 = $20.25 . . . . less at Wave Pool