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18 votes
What is the equation of the line that passes through the point (-4,-8) and has a slope of 5/2? ​

User Robnick
by
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1 Answer

19 votes
19 votes

Explanation:

Solition:

Let the line passes through the point (-4,-8) be (x1,y1) i.e. x1= -4 and y1 = -8 .

Slope(m) = 5/2

The required equation of the line passing through the point (-4,-8) is

y-y1 =m(x-x1)

or, y-(-8) = 5/2 (x-(-4))

or, y+8 = 5/2 (x+4)

or, 2(y+8) = 5(x+4)

or, 2y+16 = 5x +20

or, 16-20= 5x-2y

Therefore, 5x-2y = -4 .

User Richard Greenwood
by
3.1k points
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