Question

Consider the following balanced equation:

P4(s) + 6F2(e)
4PF3(g)
If 1.25 moles of P4(s) is reacted with 6 moles of F2(g), How many moles of PF3(e) are
produced?
O 5 moles
4 moles
O 6 moles
O 3 moles

Answer 1

Moles of PF₃ : 4

Further explanation

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

`\tt P_4(s)+6F_2(g)\rightarrow 4PF_3(g)`

1.25 moles of P₄(s) is reacted with 6 moles of F₂(g)

Limiting reactant : the smallest ratio (mol divide by coefficient)

P₄ : F₂ =

`\tt (1.25)/(1)/ (6)/(6)=1.25/ 1\rightarrow F_2~limiting~reactant(smallest~ratio)`

mol PF₃ based on mol of limiting reactant(F₂), so mol PF₃ :

`\tt (4)/(6)* 6~moles=4~moles`