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33 votes
33 votes
Calvin deposits $400 in a savings account that accrues 5% interest compounded monthly. After c years, Calvin has

$658.80. Makayla deposits $300 in a different savings account that accrues 6% interest compounded quarterly. After m
years, Makayla has $613.04. What is the in approximate difference in the number of years that Calvin and Makayla have
their money invested?
O Makayla invests her money 1 year longer.
O Makayla invests her money 2 years longer.
O Calvin invests his money 1 year longer.
O Calvin invests his money 2 years longer.

User Strikers
by
2.7k points

2 Answers

16 votes
16 votes

Answer:

Dot number 2. Makayla invests her money 2 years longer.

Explanation:

Calvin 400$ with 5% interest compounded monthly will get you to 666.0294029241$ after 13 months or 1 year and 1 month

Makayla 300$ with 6% interest quarterly

1st year 378.743088$(4 quarters)

2nd year 478.1544223592$(+4 quarters)

3rd year 603.6589415506$(+4 quarters)

3rd year and 1 quarter 639.8784780436$

User Admoghal
by
3.3k points
19 votes
19 votes

Answer:

So the second option is the answer: Makayla invests her money 2 years longer.

Explanation:

Formula for compound interest:
A=P(1+(r)/(n))^(nt)

Calvin:


A=658.80


P=400


r=0.05


n=12


t=?

Makayla:


A=613.04


P=300


r=0.06


n=4


t=?

Lets solve for
t.

1) Divide both sides of the equation by
P.


(A)/(P) =(1+(r)/(n))^(nt)

2) Take the natural log of both sides.


ln((A)/(P)) =ln((1+(r)/(n))^(nt))

3) Rewrite the right side of the equation using properties of exponents.


ln((A)/(P)) =nt*ln(1+(r)/(n))

4) Divide each side of the equation by
n*ln(1+(r)/(n))


\frac{nt*ln(1+\frac{r}n)}{n*ln(1+\frac{r}n)}=\frac{ln((A)/(P))}{n*ln(1+\frac{r}n)}

5) Cancel the common factor
n on the left side of the equation.


\frac{t*ln(1+\frac{r}n)}{ln(1+\frac{r}n)}=\frac{ln((A)/(P))}{n*ln(1+\frac{r}n)}

6) Cancel the common factor of
ln(1+(r)/(n)).


t=(ln((A)/(P)))/(n*ln(1+(r)/(n)))

Now we have an equation for
t that we can use to answer your question.

For Calvin:


t=(ln((658.80)/(400)))/(12*ln(1+(0.05)/(12)))


t=10

For Makayla:


t=(ln((613.04)/(300)))/(3*ln(1+(0.06)/(3)))


t=12

So the second option is the answer: Makayla invests her money 2 years longer.

Note: This question took me 2 minutes to answer but typing it took 30. lol

User Sergey Pleshakov
by
3.2k points