Question

Find the gretest number which devded by 181 and 236 leave a remainder of 5 in each case​

Answer 1

The greatest number is 11

Explanation:

Given

Dividends: 181 and 236

Remainder: 5

Required

Determine a divisor that satisfies the above condition

Let the required divisor be represented with x.

Since a remainder of 5 is expected, then x can divide (181 - 5) and (236 - 5) without remainders.

So, we have:

`181 - 5 = 176`

`236 - 5 = 231`

Next, we calculate the GCF of 176 and 231

`176 = 2 * 2 * 2 * 2 * 11`

`231 = 3 * 7 * 11`

The greatest common factor, GCT is:

`GCF = 11`

Hence, the required divisor is 11