Question

How many grams are there in a 14.5 moles lithium permanganate

Answer 1

There are 1825.6 g in a 14.5 moles Lithium permanganate

Further explanation

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass :

`\tt mol=(mass)/(MW)`

moles of Lithium permanganate = 14.5

Lithium permanganate (LiMnO4) MW=125.9 g/mol, so mass :

`\tt mass=mol* MW\\\\mass=14.5* 125.9~g/mol\\\\mass=1825.6~g`