Question

How much CaCO3 would have to be decomposed to produce 247 g of CaO

Answer 1

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

Further explanation

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

`\tt mol=(mass)/(MW)\\\\mol=(247)/(56)\\\\mol=4.41`

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

`\tt (1)/(1)* 4.41=4.41`

mass CaCO₃(MW=100 g/mol) :

`\tt mass=mol* MW\\\\mass=4.41* 100\\\\mass=441~g`