Question

A food processor draws 8.47 A of current when connected to a potential difference of 110 V.

How much electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day?

Answer 1

27.95[kW*min]

Step-by-step explanation:

We must remember that the power can be determined by the product of the current by the voltage.

`P=V*I`

where:

P = power [W]

V = voltage [volt]

I = amperage [Amp]

Now replacing:

`P=110*8.47\\P=931.7[W]`

Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]

`Energy = 931.7[kW]*30[days]*10[(min)/(1day) ]=279510[W*min]or 27.95[kW*min]`